6x^2-300x+2400=0

Solution for 6x^2-300x+2400=0 equation:

6x^2-300x+2400=0

a = 6; b = -300; c = +2400;
Δ = b2-4ac
Δ = -3002-4·6·2400
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-180}{2*6}=\frac{120}{12}
=10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+180}{2*6}=\frac{480}{12}
=40
$